9x^2-103x+280=0

Solution for 9x^2-103x+280=0 equation:

9x^2-103x+280=0

a = 9; b = -103; c = +280;
Δ = b2-4ac
Δ = -1032-4·9·280
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-103)-23}{2*9}=\frac{80}{18}
=4+4/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-103)+23}{2*9}=\frac{126}{18}
=7
$